Among the basic components of an Internal Combustion engine, the Connecting Rod for IC Engine is the most important and critical. The connecting rod is subjected to alternating direct compressive and tensile forces. Since the compressive forces are much higher than the tensile forces, therefore the cross-section of the connecting rod is designed as a strut and Rankine’s formula is used. In this article, we will understand the design of Connecting Rod for an IC Engine.

A connecting rod subjected to an axial load *W *may buckle with the *X*-axis as the neutral axis (*i*.*e*. in the plane of motion of the connecting rod) or the *Y*-axis as the neutral axis (*i*.*e*. in the plane perpendicular to the plane of motion).

The connecting rod is considered like both ends hinged for buckling about *X*-axis and both ends fixed for buckling about *Y*-axis. A connecting rod should be equally strong in buckling about either axes.

Let*A *= Cross-sectional area of the connecting rod*l *= Length of the connecting rod,

σ* _{c} *= Compressive yield stress

*W*= Crippling or buckling load,

_{cr}*I*and

_{xx}*I*= Moment of inertia of the section about the

_{yy}*X*-axis and

*Y*-axis respectively,

*k*and

_{xx}*k*= Radius of gyration of the section about the

_{yy}*X*-axis and

*Y*-axis respectively.

According to Rankine’s formula,

*W _{cr}* about

*X*-axis

*W _{cr}* about Y-axis

In order to have a connecting rod equally strong in buckling about both axes, the buckling loads must be equal, *i*.*e*.

This shows that the connecting rod is four times strong in buckling about *Y*-axis than about *X*-axis.

If *I _{xx} *> 4

*I*, then buckling will occur about

_{yy}*Y*-axis, and if

*I*< 4

_{xx}*I*, buckling will occur about

_{yy}*X*-axis. In actual practice,

*I*is kept slightly less than 4

_{xx}*I*.

_{yy}It is usually taken between 3 and 3.5 and the connecting rod is designed for buckling about *X*-axis. The design will always be satisfactory for buckling about *Y*-axis.

The most suitable section for the connecting rod is the *I*-section with the proportions as shown in the following figure.

Area of the section = 2 (4 *t *× *t*) + 3 *t *× *t *= 11 *t*^{2}

Moment of inertia about the *X*-axis,

and moment of inertia about the *Y*-axis,

Now, I_{xx}/I_{yy}

Since the value of I_{xx}/I_{yy} lies between 3 and 3.5, therefore *I*-section chosen is quite satisfactory.

**Notes:**

- The
*I*-section of the connecting rod is used due to its lightness and to keep the inertia forces as low as possible. It can also withstand high gas pressure. - Sometimes a connecting rod may have a rectangular section. For slow-speed engines, circular sections may be used.
- Since the connecting rod is manufactured by forging, therefore the sharp corners of the
*I*-section are rounded off as shown in the above figure for easy removal of the section from the dies.

## Design of Connecting Rod

**Problem Statement:** A connecting rod of length l may be considered as a strut with the ends free to turn on the crank pin and the gudgeon pin. In the directions of the axes of these pins, however, it may be considered as having fixed ends. Assuming that Euler’s formula is applicable, determine the ratio of the sides of the rectangular cross-section so that the connecting rod is equally strong in both planes of buckling.

**Answer:**

The rectangular cross-section of the connecting rod is shown in the following figure.

Let,*b *= Width of rectangular cross-section,*h *= Depth of rectangular cross-section.

Moment of inertia about *X-X*,

and moment of inertia about *Y-Y*,

According to Euler’s formula, buckling load,

Buckling load about *X-X*,

and buckling load about *Y-Y*,

In order to have the connecting rod equally strong in both the planes of buckling,

*W _{cr} *(

*X*-axis) =

*W*(

_{cr}*Y*-axis)

## Example problem to design a Connection Rod I-section

**Problem Statement:** Determine the dimensions of an I-section connecting rod for a petrol engine from the following data and the relations from the different Forces Acting on a Connecting Rod:

Diameter of the piston = 110 mm

Mass of the reciprocating parts = 2 kg

Length of the connecting rod from center to center = 325 mm

Stroke length = 150mm

Speed in R.P.M. = 1500 with a possible Overspeed of 2500

Compression ratio = 4: 1

Maximum explosion pressure = 2.5 N/mm^{2}

**Answer:**

We know that the radius of the crank, r = Stroke length /2 150 / 2 = 75mm = 0.075m

The ratio of the length of connecting rod to the radius of the crank n = l/r = 325/75 = 4.3

We know that the maximum force on the piston due to pressure,

The maximum angular speed from the previous article,

We know that the maximum inertia force of reciprocating parts from the previous article,

The inertia force of reciprocating parts is maximum when the crank is at the inner dead center, *i*.*e*. when θ = 0°

Since the connecting rod is designed by taking the force in the connecting rod (*F*_{C}) equal to the maximum force on the piston due to gas pressure (*F*_{L}), therefore

Force in the connecting rod, *F*_{C} = *F*_{L} = 23760N

Consider the *I*-section of the connecting rod with the proportions as shown in the following figure.

We have also discussed that the connecting rod is designed for buckling about the *X*-axis (*i*.*e*. in a plane of motion of the connecting rod), assuming both ends are hinged. Taking a factor of safety as 6, the buckling load,

*W _{cr} *=

*F*

_{C}× 6 = 23760 × 6 = 142560N

and area of cross-section, *A *= 2 (4*t *× *t*) + *t *× 3*t *= 11 *t*^{2} mm^{2}

Moment of inertia about the *X*-axis,

The radius of gyration,

We know that the equivalent length of the rod for both ends is hinged, L = l = 325mm

Taking for mild steel, σ* _{c} *= 320 MPa = 320 N/mm

^{2}and

*a*= 1 / 7500, we have from Rankine’s formula,

Therefore, the dimensions of the cross-section of the connecting rod are

Height = 5*t* = 5 × 6.8 = 34mm

Width = 4*t* = 4 × 6.8 = 27.2mm

The thickness of flange and web = *t* = 6.8mm = 0.0068m

From these parameters, we can design the Connecting Rod for IC Engine. Let us know what you think about this article in the comment section below.

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